-5x^2-3x+10=0

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Solution for -5x^2-3x+10=0 equation: 



-5x^2-3x+10=0

a = -5; b = -3; c = +10;
Δ = b2-4ac
Δ = -32-4·(-5)·10
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{209}}{2*-5}=\frac{3-\sqrt{209}}{-10}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{209}}{2*-5}=\frac{3+\sqrt{209}}{-10}
$

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